chemistry gas laws answers
2.00 atm at constant temperature, what is the new volume? Solution: Identify knowns: \(V_1 = 10.0\,L\) \(P_1 = 1.00\,atm\) \(P_2 = 2.00\,atm\) Find \(V_2\) Apply Boyle’s Law: \[ P_1 V_1 = P_2 V_2 \] Rearranged: \[ V_2 = \frac{P