Half Life Problems Answers
200 grams to 25 grams and the half-life is 4 years, how much time has passed? Solution: \[ t = \frac{T_{1/2}}{\log(2)} \times \log\left(\frac{N_0}{N(t)}\right) = \frac{4}{0.3010} \times \log\left(\frac{200}{25}\right) \] \[ = 13.29 \times \l