electrochemistry problems and answers
iply oxidation by 5: \[ 5 \text{Fe}^{2+} \rightarrow 5 \text{Fe}^{3+} + 5e^- \] Keep reduction as is. Add the two half-reactions: \[ \text{MnO}_4^- + 8H^+ + 5e^- + 5 \text{Fe}^{2+} \rightarrow \text{Mn}^{2+} + 4H_2O + 5 \text{Fe